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Question 1:

What is a precipitation reaction?

A) A reaction that produces a gas
B) A reaction that produces a solid
C) A reaction that produces a liquid
D) A reaction that produces heat

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Explanation: The correct answer is B) A reaction that produces a solid. A precipitation reaction is a type of chemical reaction in which two soluble compounds react to form an insoluble solid called a precipitate.

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Question 2:

What is the driving force for a precipitation reaction?

A) Formation of a gas
B) Formation of a liquid
C) Formation of a solid
D) Formation of heat

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Explanation: The correct answer is C) Formation of a solid. In a precipitation reaction, the driving force is the formation of an insoluble solid (precipitate) when two soluble compounds come into contact and react.

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Question 3:

What is the product of the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl)?

A) Silver nitrate (AgNO3) + Sodium chloride (NaCl)
B) Sodium nitrate (NaNO3) + Silver chloride (AgCl)
C) Silver nitrate (AgNO3) + Silver chloride (AgCl)
D) Sodium nitrate (NaNO3) + Sodium chloride (NaCl)

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Explanation: The correct answer is B) Sodium nitrate (NaNO3) + Silver chloride (AgCl). The reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) results in the formation of sodium nitrate (NaNO3) and silver chloride (AgCl), which is insoluble and precipitates out.

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Question 4:

What is the precipitate formed when calcium chloride (CaCl2) reacts with sodium carbonate (Na2CO3)?

A) Sodium chloride (NaCl)
B) Calcium carbonate (CaCO3)
C) Sodium carbonate (Na2CO3)
D) Calcium chloride (CaCl2)

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Explanation: The correct answer is B) Calcium carbonate (CaCO3). When calcium chloride (CaCl2) reacts with sodium carbonate (Na2CO3), the insoluble precipitate formed is calcium carbonate (CaCO3), which appears as a solid.

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Question 5:

What is the net ionic equation for the reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI)?

A) Pb(NO3)2 + KI → PbI2 + KNO3
B) Pb(NO3)2 + KI → Pb(NO3)2 + KI
C) Pb(NO3)2 + KI → PbI2 + 2KNO3
D) Pb(NO3)2 + KI → PbI2 + KI

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Explanation: The correct answer is A) Pb(NO3)2 + 2KI → PbI2 + 2KNO3. The net ionic equation for the reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is Pb2+ + 2I- → PbI2, indicating the formation of lead(II) iodide (PbI2).